Solved by a verified expert:Assume Km = 2 x 10-3; Ki = 1.5 x 10-4 and Vmax = 270 nmoles/l/min. Calculate vi and the degree (%) of inhibition caused by a competitive inhibitor under the following conditions: a) [S] = 2 x 10-3 M an [I] = 2 x 10-3 M b) [S] = 4 x 10-4 M an [I] = 2 x 10-3 M c) [S] = 7.5 x 10-3 M an [I] = 1 x 10-5 M
Expert answer:Assume Km = 2 x 10-3; Ki = 1.5 x 10-4 and Vmax = 2
by | Sep 2, 2021 | Uncategorized
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